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Exhibit 6.5 Data analysis tool for paired two-sample means
for rejection of the null hypothesis, 2.030110409 (cell B14). Thus, we reject the
null and accept the alternative that the training does make a difference. The p-value
is miniscule, 4.62055E-17 (cell B13), and far smaller than the 0.05 level set for
α
, which of course similarly suggests rejection of the null. The question remains
Table 6.7 Test of matched samples SC prisoner scores
 
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